DatePart Function
The DatePart function returns a specified part of a date.
DatePart (interval As String, date As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Long
Return value:
The extracted part for the given date.
interval - A string expression from the following table, specifying the date interval.
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interval (string value)
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Explanation
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yyyy
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Year
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q
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Quarter
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m
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Month
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y
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Day of year
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w
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Weekday
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ww
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Week of year
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d
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Day
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h
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Hour
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n
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Minute
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s
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Second
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date - The date from which the result is calculated.
Date literals allow to specify unambiguous date variables that are independent from the current language. Literals are enclosed between hash signs #. Possible formats are:
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#yyyy-mm-dd#
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#mm/dd/yyyy#
firstdayofweek: An optional parameter that specifies the starting day of a week.
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firstdayofweek value
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Explanation
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0
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Use system default value
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1
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Sunday (default)
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2
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Monday
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3
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Tuesday
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4
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Wednesday
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5
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Thursday
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6
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Friday
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7
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Saturday
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firstweekofyear: An optional parameter that specifies the starting week of a year.
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firstweekofyear value
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Explanation
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0
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Use system default value
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1
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Week 1 is the week with January, 1st (default)
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2
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Week 1 is the first week containing four or more days of that year
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3
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Week 1 is the first week containing only days of the new year
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Sub example_datepart
MsgBox DatePart("ww", #12/31/2005#)
MsgBox DatePart(date:=#1999-12-30#, interval:="q")
End Sub