DateDiff Function
Returns the number of date intervals between two given date values.
Syntax:
DateDiff (Add, Date1, Date2 [, Week_start [, Year_start]])
Return value:
A number.
Parameters:
Add - A string expression from the following table, specifying the date interval.
Date1, Date2 - The two date values to be compared.
Week_start - An optional parameter that specifies the starting day of a week.
|
Week_start value |
Explanation |
|
0 |
Use system default value |
|
1 |
Sunday (default) |
|
2 |
Monday |
|
3 |
Tuesday |
|
4 |
Wednesday |
|
5 |
Thursday |
|
6 |
Friday |
|
7 |
Saturday |
Year_start - An optional parameter that specifies the starting week of a year.
|
Year_start value |
Explanation |
|
0 |
Use system default value |
|
1 |
Week 1 is the week with January, 1st (default) |
|
2 |
Week 1 is the first week containing four or more days of that year |
|
3 |
Week 1 is the first week containing only days of the new year |
Example:
Sub example_datediff
MsgBox DateDiff("d", "1/1/2005", "12/31/2005")
End Sub